70.7k views
3 votes
Write the electron configurations of these elements:

Si (long) = _______________________________
Se (long) = _______________________________
Pd (noble gas) = _______________________________
Tl (noble gas) = _______________________________
Francium (noble gas) = ____________________________ .

User Pungggi
by
7.6k points

1 Answer

4 votes

Final answer:

The electron configurations for Si, Se, Pd, Tl, and Francium are 1s² 2s² 2p¶ 3s² 3p², 1s² 2s² 2p¶ 3s² 3p¶ 4s² 3d±° 4p´, [Kr] 4d±°, [Xe] 4f¹´ 5d±° 6s² 6p¹, and [Rn] 7s¹ respectively.

Step-by-step explanation:

The electron configurations of the given elements are as follows:

Si (Silicon): 1s² 2s² 2p¶ 3s² 3p²

Se (Selenium): 1s² 2s² 2p¶ 3s² 3p¶ 4s² 3d±° 4p´

Pd (Palladium) using noble gas notation: [Kr] 4d±°

Tl (Thallium) using noble gas notation: [Xe] 4f¹´ 5d±° 6s² 6p¹

Francium using noble gas notation: [Rn] 7s¹

Remember that the noble gas notation is a simplified version of the long electron configuration where the core electrons are represented by the symbol of the noble gas from the preceding period.

User SystemParadox
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.