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Write the electron configurations of these elements:

Si (long) = _______________________________
Se (long) = _______________________________
Pd (noble gas) = _______________________________
Tl (noble gas) = _______________________________
Francium (noble gas) = ____________________________ .

User Pungggi
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1 Answer

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Final answer:

The electron configurations for Si, Se, Pd, Tl, and Francium are 1s² 2s² 2p¶ 3s² 3p², 1s² 2s² 2p¶ 3s² 3p¶ 4s² 3d±° 4p´, [Kr] 4d±°, [Xe] 4f¹´ 5d±° 6s² 6p¹, and [Rn] 7s¹ respectively.

Step-by-step explanation:

The electron configurations of the given elements are as follows:

Si (Silicon): 1s² 2s² 2p¶ 3s² 3p²

Se (Selenium): 1s² 2s² 2p¶ 3s² 3p¶ 4s² 3d±° 4p´

Pd (Palladium) using noble gas notation: [Kr] 4d±°

Tl (Thallium) using noble gas notation: [Xe] 4f¹´ 5d±° 6s² 6p¹

Francium using noble gas notation: [Rn] 7s¹

Remember that the noble gas notation is a simplified version of the long electron configuration where the core electrons are represented by the symbol of the noble gas from the preceding period.

User SystemParadox
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