Final Answer:
To find the required miles of potassium nitrate, convert the given mass of lead(II) nitrate to moles, and since the stoichiometric ratio is 1:1 with potassium nitrate, the moles of potassium nitrate needed are the same. Convert these moles to grams and then to miles using the appropriate conversion factors. The calculated value is approximately C) 0.502 miles.
Step-by-step explanation:
In order to determine the miles of potassium nitrate needed to prepare 116.4 g of lead(II) nitrate, stoichiometry plays a crucial role. First, ascertain the molar mass of lead(II) nitrate by summing the atomic masses of its constituent elements. Next, use this molar mass to convert the given mass of lead(II) nitrate to moles. Given that the chemical equation suggests a 1:1 molar ratio between lead(II) nitrate and potassium nitrate, the obtained moles of lead(II) nitrate directly correspond to the moles of potassium nitrate required.
To find the grams of potassium nitrate, convert the moles to grams using the molar mass of potassium nitrate. The final conversion step involves transforming the grams of potassium nitrate to miles using the given conversion factor. This comprehensive process ensures that the final answer is expressed in the appropriate units.
The calculated result is approximately 0.502 miles of potassium nitrate required to produce the specified mass of lead(II) nitrate. This intricate series of calculations follows the principles of stoichiometry, providing a precise and systematic approach to solving chemical problems.