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Two students travel from school to their jobs at the bowling alley, which is 2.5 km away. One student rides a scooter at 0.9 m/s, and the other student rides a bike at 12 mi/hr. How long does the trip take for each of them?

User Squidly
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1 Answer

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Final answer:

The student on the scooter will take approximately 46.3 minutes, while the student on the bike will take approximately 7.77 minutes to travel the 2.5 km distance to the bowling alley.

Step-by-step explanation:

To calculate the travel time for each student from school to their job at the bowling alley, we need to convert the speeds into compatible units and then use the formula time = distance/speed.

For the student on the scooter traveling at 0.9 m/s:


  • First, we convert the distance from km to meters: 2.5 km = 2,500 meters.

  • Then, we calculate the travel time:

    Time = Distance / Speed

    Time = 2,500 meters / 0.9 m/s = 2,777.78 seconds.

  • Finally, convert seconds to minutes: 2,777.78 seconds ≈ 46.3 minutes.

For the student on the bike traveling at 12 mi/hr:


  • First, convert the speed from mi/hr to km/hr: 12 mi/hr = 19.3121 km/hr.

  • Next, calculate the travel time:

    Time = Distance / Speed

    Time = 2.5 km / 19.3121 km/hr = 0.1295 hours.

  • Finally, convert hours to minutes: 0.1295 hours ≈ 7.77 minutes.

Therefore, the student riding the scooter will take approximately 46.3 minutes, and the student riding the bike will take approximately 7.77 minutes to travel from school to the bowling alley.

User Askar
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