Question

A toddler rolls off of his bed and hits the floor with a thud 0.53m below. If he lands 0.2m away from the base of the bed, how long did he fall for?

A. t = ? (time)
B. dy = 0.53m (vertical distance)
C. dx = 0.2m (horizontal distance)
D. ay = ? (acceleration in the vertical direction)

Answer 1

The toddler fell for approximately 0.32 seconds.

Step-by-step explanation:

To calculate the time the toddler fell for, we can use the equations of motion. The equation that relates distance, initial velocity, time, and acceleration is dy = (1/2)ayt^2. In this case, the distance dy = 0.53m and the acceleration in the vertical direction ay can be taken as the acceleration due to gravity, which is approximately 9.8 m/s^2. Plugging in these values, we get:

0.53 = (1/2)(9.8)t^2

Solving for t gives us t = 0.32 seconds. Therefore, the toddler fell for approximately 0.32 seconds.