Question

Find the equation of the circle with a center at (-2, -6) and a solution point (1, -10).

a) (x + 2)^2 + (y + 6)^2 = 9
b) (x - 2)^2 + (y - 6)^2 = 9
c) (x + 2)^2 + (y - 6)^2 = 9
d) (x - 2)^2 + (y + 6)^2 = 9

Answer 1

The equation of the circle with center (-2, -6) and solution point (1, -10) is (x + 2)^2 + (y + 6)^2 = 9.

Step-by-step explanation:

The equation of a circle with a center at (-2, -6) and a solution point (1, -10) can be found using the standard form equation of a circle, which is (x - h)^2 + (y - k)^2 = r^2. In this equation, (h, k) represents the center of the circle and r represents the radius.

So, substituting the given values, we get:

(x + 2)^2 + (y + 6)^2 = (1 - (-2))^2 + (-10 - (-6))^2

Simplifying further, (x + 2)^2 + (y + 6)^2 = 9.