Final answer:
The artificial satellite experiences an acceleration due to gravity that is less than the standard 9.8 m/s² due to its altitude above the Earth's surface.
Step-by-step explanation:
The question is asking for the acceleration due to gravity experienced by an artificial satellite orbiting the Earth at a height of 200 km above the Earth's surface. To calculate this, we can use the formula for gravitational acceleration at a distance r from the center of the Earth: g = G*M/(R+h)^2, where G is the gravitational constant, M is the mass of the Earth, R is the radius of the Earth, and h is the height of the satellite above the Earth's surface. Given that the radius of the Earth (R) is about 6371 km and adding the height of the satellite (h), we get r = R + h = 6571 km or 6571000 m. We then square this value and use the mass of the Earth and gravitational constant to find g. The correct answer is not the standard 9.8 m/s² because the satellite is above the Earth's surface where gravitational acceleration is slightly weaker.