Question

Graph the following system of equationsy=2^xy=(x+1)^3 -1

Answer 1

V, this is the solution:

Part A:

y = 2^x

Let's recall that exponential equations have a horizontal asymptote.

In consequence, horizontal asymptote: y = 0

Part B

Let's find the coordinates for this equation:

y = (x + 1) ^3 - 1

x y

-3 -9

-2 -2

-1 -1

0 0

1 7

2 26

In consequence, the graph for this equation is: