Question

Danyka (mass 57 kg), Faiqa (mass 54 kg), and Serena (mass 53 kg) were riding on a "bicycle-built-for-three," which had a mass of 15 kg. Although all three rode at the same time, only one was able to pedal. Calculate the work done by each rider: Danyka started the bike moving and sped up to 8.0 km/h, Faiqa took the second shift and got them up to 16 km/h, and Serena took the final shift and took them up to 24 km/h.

A) Danyka: 1960 J, Faiqa: 3920 J, Serena: 5880 J
B) Danyka: 3920 J, Faiqa: 7840 J, Serena: 11760 J
C) Danyka: 2940 J, Faiqa: 5880 J, Serena: 8820 J
D) Danyka: 11760 J, Faiqa: 23520 J, Serena: 35280 J

Answer 1

Danyka: 281 J, Faiqa: 532 J, Serena: 788 J

Step-by-step explanation:

To calculate the work done by each rider, we can use the equation:

Work = Force × Distance

First, let's convert the speeds from km/h to m/s:

Danyka: 8.0 km/h = 8.0 × (1000/3600) m/s = 2.22 m/s

Faiqa: 16 km/h = 16 × (1000/3600) m/s = 4.44 m/s

Serena: 24 km/h = 24 × (1000/3600) m/s = 6.67 m/s

Now we can calculate the work done by each rider:

Danyka: Work = Force × Distance = (57 kg × 2.22 m/s^2) × 2.22 m = 280.9896 J ≈ 281 J

Faiqa: Work = Force × Distance = (54 kg × 4.44 m/s^2) × 2.22 m = 532.2248 J ≈ 532 J

Serena: Work = Force × Distance = (53 kg × 6.67 m/s^2) × 2.22 m = 787.8262 J ≈ 788 J

Therefore, the work done by each rider is:

Danyka: 281 J

Faiqa: 532 J

Serena: 788 J