Question

A student on a tower 49 m height drops a stone. One second later he throws a second stone3 the first. They both hit the ground at the same time with what speed does he throw the[Ans: 10.1 m/ssecond stone.36Reliant Science -10​

A. 10.1 m/s
B. 9.8 m/s
C. 11.5 m/s
D. 12.2 m/s

Answer 1

To find the speed with which the second stone is thrown, we can use the concept of projectile motion. Since both stones hit the ground at the same time, we know that they have the same time of fall. The student threw the second stone with a speed of approximately 21.2 m/s.

Step-by-step explanation:

To find the speed with which the second stone is thrown, we can use the concept of projectile motion. Since both stones hit the ground at the same time, we know that they have the same time of fall. Let's consider the first stone, which was dropped from a height of 49 m. Using the equation for free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of fall, we can solve for t. Plugging in the values, 49 = (1/2)(9.8)(t^2), we find t = 3.16 s. Since the second stone was thrown 1 second later, its time of fall will be 3.16 - 1 = 2.16 s.

Now, to find the speed of the second stone when it hits the ground, we can use the equation v = gt, where v is the final velocity and g is the acceleration due to gravity. Plugging in the values, v = (9.8)(2.16) ≈ 21.2 m/s. Therefore, the student threw the second stone with a speed of approximately 21.2 m/s.