Final answer:
To solve for x and y in the geometry problem relating to the angles and parallel lines given, we would set up a system of equations using the information about the angles provided. However, we need additional context or information about the angles' relationships to provide a definitive answer.
Step-by-step explanation:
The problem given is a mathematical exercise in solving systems of equations. As stated, the city of Newport News is creating a new subdivision with parallel roads, giving rise to a geometry problem involving angles. We are given that m Z1 = (x+3y), m Z2 = 130°, and m Z3 = (3x-y). To find the values of x and y, we will assume that Z1 and Z3 represent angles of parallel lines and thus are equal to each other because they would be corresponding angles. Setting their expressions equal to one another gives us (x+3y) = (3x-y). Simplifying yields:
We also know that one of the angles is 130 degrees, so that could be Z1 or Z3 if they are indeed corresponding angles on parallel lines. We can set (x+3y) = 130 or (3x-y) = 130 and substitute x for 2y (from our first equation) to find the values of x and y. Solving these equations should lead us to the right answer.
However, the information provided in the question does not seem to relate directly to proving p/q nor is it sufficient to calculate x or y without additional information or assumptions. If there is additional context about the relationship between Z1, Z2, and Z3 or about these angles' relationship to the geometry of the subdivision that has been omitted here, that information would be necessary to find x and y and to 'prove p/q', which might be a typo or an unrelated part of a larger geometry problem.