Question

A cat walking at 0.56m/s sees a mouse and accelerates uniformly at 0.40 m/s² for 3.0 s. What is the cat's displacement

during this time?

Answer 1

The cat's displacement as it accelerates for 3.0 seconds at an acceleration of 0.40 m/s² from an initial speed of 0.56 m/s is 3.48 meters.

Step-by-step explanation:

To find the cat's displacement during the time it accelerates, we can use the formula for displacement with constant acceleration, which is:

s = ut + ½at²

where:

• s is the displacement
• u is the initial velocity
• a is the acceleration
• t is the time

In this scenario, the cat's initial velocity (u) is 0.56 m/s, the acceleration (a) is 0.40 m/s², and the time (t) is 3.0 s. Plugging these values into the formula:

s = (0.56 m/s)(3.0 s) + ½(0.40 m/s²)(3.0 s)²

s = 1.68 m + ½(0.40 m/s²)(9 s)

s = 1.68 m + 1.8 m

s = 3.48 m

Therefore, the cat's displacement is 3.48 meters.