Question

Which equation would graph a line that passes through the point (12,0) and is perpendicular to the graph of the equation y = 6x- 1?

A. y = 63 - 1
B. y = 60 - 12
C. y= - 1/6x + 2
D. y=-1/6x - 1

Answer 1

To find the equation of a line that is perpendicular to y = 6x - 1 and passes through the point (12,0), the equation y = -1/6x + 2 would be graphed.

Step-by-step explanation:

To find the equation of a line that is perpendicular to the graph of the equation y = 6x - 1 and passes through the point (12,0), we need to determine the slope of the perpendicular line. The slope of the original line is 6, so the slope of the perpendicular line will be the negative reciprocal of 6, which is -1/6. Using the point-slope form of a linear equation, y - y1 = m(x - x1), we can substitute the values into the equation to find the equation of the perpendicular line.

Substituting the point (12,0) and the slope -1/6 into the equation, we get:
y - 0 = -1/6(x - 12)
Then simplifying the equation:
y = -1/6x + 2

So, the equation that would graph a line passing through the point (12,0) and perpendicular to the graph of y = 6x - 1 is y = -1/6x + 2.