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If 9^(2x-2) = 81^(2x-3), then what is the value of x?

User Chihung Yu
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1 Answer

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Final answer:

To solve the equation 9^(2x-2) = 81^(2x-3), we can simplify both sides by using the fact that 81 = 9^2. By equating the exponents, the value of x is found to be 2.

Step-by-step explanation:

To solve the equation 9^(2x-2) = 81^(2x-3), we can simplify both sides by using the fact that 81 = 9^2. Thus, we have:

9^(2x-2) = (9^2)^(2x-3)

Using the property of exponents, we can multiply the exponents:

9^(2x-2) = 9^(4x-6)

Now, by comparing the bases on both sides, we can equate the exponents:

2x-2 = 4x-6

Subtract 2x from both sides:

-2 = 2x-6

Add 6 to both sides:

4 = 2x

Divide both sides by 2:

x = 2

User Narzero
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