Question

During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items.2468101214# items over 100.51.52.53.54.55.56.57.5Frequency[Graphs generated by this script: setBorder(54,40,20,5); initPicture(0,7.5,0,14);axes(1000,2,1,1000,2); fill="blue"; textabs([165,0],"# items over 10","above");line([0.5,-0.28],[0.5,0.28]); text([0.5,0],"0.5","below");line([1.5,-0.28],[1.5,0.28]); text([1.5,0],"1.5","below");line([2.5,-0.28],[2.5,0.28]); text([2.5,0],"2.5","below");line([3.5,-0.28],[3.5,0.28]); text([3.5,0],"3.5","below");line([4.5,-0.28],[4.5,0.28]); text([4.5,0],"4.5","below");line([5.5,-0.28],[5.5,0.28]); text([5.5,0],"5.5","below");line([6.5,-0.28],[6.5,0.28]); text([6.5,0],"6.5","below");line([7.5,-0.28],[7.5,0.28]); text([7.5,0],"7.5","below");textabs([0,115],"Frequency","right",90);rect([0.5,0],[1.5,6]);rect([1.5,0],[2.5,10]);rect([2.5,0],[3.5,11]);rect([3.5,0],[4.5,14]);rect([4.5,0],[5.5,12]);rect([5.5,0],[6.5,8]);rect([6.5,0],[7.5,4]);]What is the frequency of times the limit was exceeded by less than 4 items?ans =

Answer 1

Step-by-step explanation: 59

Answer 2

The frequency of times the limit is exceeded by less than 4 items is calculated by adding up the frequencies for the bars representing 1, 2, and 3.

The individual frequencies are given as shown below:

`\begin{gathered} 1\text{ item more}\Rightarrow6 \\ 2\text{ items more}\Rightarrow10 \\ 3\text{ items more}\Rightarrow11 \end{gathered}`

Hence, the number of times the limit was exceeded by less than 4 items is calculated to be:

`\Rightarrow6+10+11=27`

The frequency is 27.