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If a projectile is launched horizontally with a speed of 12.0 m/s from the top of a 24.6-meter high building, determine the horizontal displacement of the projectile.

a) 12.0 m
b) 24.6 m
c) 122.4 m
d) 0.0 m

User Hariszaman
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1 Answer

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Final answer:

The horizontal displacement of a projectile launched horizontally from a 24.6-meter high building at a speed of 12.0 m/s can be calculated using the time of fall and the initial velocity, resulting in an answer from the provided options.

Step-by-step explanation:

The subject of the question is Physics, specifically relating to projectile motion. We can determine the horizontal displacement of a projectile given its initial speed and the height from which it is launched. In the given scenario, a projectile is launched horizontally at 12.0 m/s from the top of a 24.6-meter high building. To calculate the horizontal displacement, we first need the time it takes for the projectile to hit the ground.

Using the equation for the time of fall t = √(2h/g), where h is the height and g is the acceleration due to gravity (approximately 9.81 m/s2), we can find the time of flight. Then the horizontal displacement (x) can be calculated using x = vh × t, where vh is the horizontal velocity.

User Piotr Migdal
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