Question

4.00L of helium at 35.0°C is cooled to 5.00°C. What is the volume of the helium at 5.00°C?

Answer 1

Using Charles's Law, the volume of helium gas cooled from 35.0°C to 5.00°C is calculated to be 3.61 L. Temperature conversions to Kelvin and the volume-temperature proportionality relationship are applied to find this result.

Step-by-step explanation:

The student's question concerns the change in volume of helium gas when it is cooled from an initial temperature to a lower one. To calculate the final volume of helium at 5.00°C, we can use the Charles's Law which states that the volume of a gas is directly proportional to its temperature in kelvin, provided that the pressure is constant.

First, convert the temperatures from Celsius to Kelvin by adding 273.15: Initial temperature (T1) = 35.0°C = 308.15 K and final temperature (T2) = 5.00°C = 278.15 K.

Using Charles's Law, V1/T1 = V2/T2, we can solve for the final volume (V2), given that the initial volume (V1) is 4.00 L:

V2 = V1 * (T2/T1)

V2 = 4.00 L * (278.15 K / 308.15 K)

V2 = 4.00 L * 0.9025

V2 = 3.61 L

Thus, the volume of the helium at 5.00°C is 3.61 L.