Question

Given A = 2102 + bz)h, solve for h.

A) h = 2A(61 + b)
B) h = b + b^2 / 2A
C) h = b(1 + b^2) / 2A
D) h = A - 3(0^2 + b^2)

Answer 1

To solve for h in the equation A = 2102 + bz)h, isolate h by subtracting 2102 from both sides and then dividing by bz.

Step-by-step explanation:

To solve for h in the given equation A = 2102 + bz)h, we need to isolate h on one side of the equation. By subtracting 2102 from both sides of the equation, we have A - 2102 = bz)h.

To further isolate h, we divide both sides of the equation by (bz), giving us (A - 2102)/(bz) = h.

Therefore, the solution for h is h = (A - 2102)/(bz).