Final answer:
The time it takes for a ball thrown upwards with an initial velocity of 15 m/s to reach maximum height is approximately 1.53 seconds using the formula t = v0/g, where g is the acceleration due to gravity (9.81 m/s^2).
Step-by-step explanation:
To calculate the time it takes for a ball thrown upwards with an initial velocity to reach its maximum height, we can use the kinematics equation for uniformly accelerated motion. The acceleration in this case is due to gravity, which on Earth's surface has a value of approximately 9.81 m/s2 in the downward direction. The formula to use is t = v0/g, where t is the time to reach the maximum height, v0 is the initial velocity, and g is the acceleration due to gravity.
For an initial velocity of 15 m/s, the calculation would be:
t = v0/g = 15 m/s / 9.81 m/s2
After performing the division, we find that t equals approximately 1.53 seconds. This is the time it takes for the ball to go from the point of release to its highest point before it starts to fall back down again.