Question

For $1200, a business can post an advertisement for 30 days. For $10, the advertisement will be posted for 60 days. The relationship comparing cost and the number of days, x, that an advertisement will be posted is linear. Which function can be used to model the relationship?

Options:
A. y = 300x + 1200
B. y = 1200x + 300
C. y = 10x + 900
D. y = 900x + 10

Answer 1

The function that can be used to model the relationship between cost and the number of days an advertisement will be posted is y = 10x + 900.

Step-by-step explanation:

To model the relationship between cost and the number of days an advertisement will be posted, we need to find a linear function. We can start by looking at the options provided:

A. y = 300x + 1200

B. y = 1200x + 300

C. y = 10x + 900

D. y = 900x + 10

To determine the correct function, we can use the information given in the question:

For $1200, the advertisement is posted for 30 days.

This can be represented as the point (30, 1200).

For $10, the advertisement is posted for 60 days.

This can be represented as the point (60, 10).

We can now substitute the x and y values into each of the functions to see which one gives us the correct output.

Option B, y = 1200x + 300, gives us y = 1200(30) + 300 = 37200, which is not equal to 1200.

Option C, y = 10x + 900, gives us y = 10(60) + 900 = 1500, which is equal to 1200.

Therefore, the correct function is y = 10x + 900.