Question

A cellphone company charges an initial fee of $35 and then $40 per month. (Hint: write this situation as an equation in slope-intercept form). Which equation has the SAME rate of change?

A) y = 35x
B) y = 40x
C) y = 35 + 40x
D) y = 40 + 35x

Select the equation that has the same rate of change as the given situation.""

Answer 1

The equation that represents the given situation and has the same rate of change is y = 35 + 40x.

Step-by-step explanation:

The given situation can be represented by the equation y = 35 + 40x.

The initial fee of $35 is represented by the constant term, and the $40 per month is represented by the coefficient of x.

Therefore, the equation that has the same rate of change is y = 35 + 40x (option C).

Answer 2

The equation that has the same rate of change as the cellphone company's charges, with an initial fee of $35 and $40 per month, is C) y = 35 + 40x, as it has the same slope (rate of change) of 40.

Step-by-step explanation:

The equation representing a cellphone company that charges an initial fee and a monthly fee is in the slope-intercept form, which is y = mx + b, where m is the slope (rate of change) and b is the y-intercept (initial fee). In this case, the company charges a one-time fee of $35 and then $40 per month. Therefore, the equation can be written as y = 40x + 35.

The equation that has the same rate of change as the given situation is the one with the same slope, which represents the monthly charge. In this case, C) y = 35 + 40x has the same rate of change, since the coefficient of x is 40, which stands for the $40 monthly fee the company charges.