Final answer:
The correct scenario is where CD is perpendicular to line q at point D within plane X; plane Y intersects X at line s, which is parallel to line l. Point C is common to CD and line l.
Step-by-step explanation:
To address the student's question, we will begin by conceptualizing the scenario described and using geometry terms to label the figures. When two lines or segments are perpendicular, they intersect to form right angles (90°). When a line is parallel to another, it means they extend in the same direction without ever intersecting, regardless of their length. When a plane intersects another plane, the intersection is a line. Lastly, when any figure (line or plane) is perpendicular to a plane, it means it intersects the plane at a right angle.
In this situation, if CD is perpendicular to line q, it suggests that they intersect at a right angle at point D, and D must lie on both CD and q. For plane Y to intersect plane X creating line s, line s should be drawn as the intersection of the two planes. Since CD is perpendicular to line s at point C, C must lie on both CD and s. If line l intersects CD at point C, line l would also have to contain point C. However, the condition that line s is parallel to line l indicates that they cannot intersect, thus s and l extend in the same direction without crossing each other.
Considering all these conditions, the correct answer seems to match the description in part a). CD intersects line q at point D, which lies in plane X; line s is the intersection between planes X and Y and is parallel to line l; plane Y intersects plane X, confirming that one of the intersections is, indeed, line s.