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What is the slope of the line perpendicular to the line in the previous question? 49 = 3x + 7y

User Jazaman
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Final answer:

The slope of a line perpendicular to another line can be found by taking the negative reciprocal of the slope of the original line. In this case, the slope of the line perpendicular to 49 = 3x + 7y is 7/3.

Step-by-step explanation:

The slope of a line perpendicular to another line can be found by taking the negative reciprocal of the slope of the original line. In the previous question, the equation of the line is given as 49 = 3x + 7y. To find its slope, we need to rearrange the equation into the slope-intercept form (y = mx + b), where m is the slope. The equation can be rewritten as y = (-3/7)x + (49/7). Therefore, the slope of the line is -3/7. To find the slope of a line perpendicular to this, we take the negative reciprocal, which is 7/3.

User Ali Raza
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