Final answer:
There are approximately 6.28 × 10²² molecules of N2 in 2.34 L of N2 by using Avogadro's law and Avogadro's number to calculate this from the given volume.
Step-by-step explanation:
To answer the question of how many molecules of N2 are in 2.34 L of N2, we need to use Avogadro's law, which states that one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, to find the number of moles of N2 in 2.34 L, we would divide the volume by the molar volume at STP which is 22.4 L/mol.
We calculate the moles of N2 as follows:
Number of moles (n) = Volume (V) / Molar volume (Vm) = 2.34 L / 22.4 L/mol = 0.10446428571 moles of N2
Then we use Avogadro's number, which is 6.02 × 10²³ molecules/mol, to calculate the number of molecules:
Number of molecules (N) = n × Avogadro's number = 0.10446428571 moles × 6.02 × 10²³ molecules/mol
Therefore, there are approximately 6.28 × 10²² molecules of N2 in 2.34 L of N2.