Question

Over a period of 23 s an object experienced an acceleration of 4.6 m/s2. It had been initially traveling at 7.6 m/s. How fast will it be moving at the end of the 23 seconds?

Answer 1

To find the final velocity of an object after 23 seconds of constant acceleration, use the kinematic equation v = u + at. With an initial velocity of 7.6 m/s and an acceleration of 4.6 m/s², the object will be moving at 113.4 m/s at the end of the period.

Step-by-step explanation:

To calculate how fast an object will be moving at the end of a certain time period if it is subject to constant acceleration, we can use the kinematic equation:

v = u + at

where:

• v is the final velocity,
• u is the initial velocity,
• a is the acceleration,
• t is the time.

In the question provided, the object starts with an initial velocity (u) of 7.6 m/s and accelerates at a rate of 4.6 m/s² over a period of 23 seconds (t). Plugging these values into the equation, we get:

v = 7.6 m/s + (4.6 m/s² × 23 s)

Now, conduct the multiplication and addition:

v = 7.6 m/s + 105.8 m/s = 113.4 m/s

Therefore, at the end of the 23 seconds, the object will be moving at 113.4 m/s.