Question

If f(x) = 2x³ + 15x² – 47x + 30 and f(-10) = 0, then find all of the zeros of f(x) algebraically.

a) x = 2, x = -3, x = -5
b) x = -2, x = 3, x = 5
c) x = -2, x = -3, x = 5
d) x = 2, x = 3, x = -5

Answer 1

The zero of the function f(x) = 2x³ + 15x² - 47x + 30 is x = -10.

Step-by-step explanation:

To find the zeros of the function f(x), we need to find the values of x for which f(x) = 0. Given that f(x) = 2x³ + 15x² - 47x + 30, and f(-10) = 0, we can substitute x = -10 into the function to get:

2(-10)³ + 15(-10)² - 47(-10) + 30 = 0

Expanding and simplifying, we get:

-2000 + 1500 + 470 + 30 = 0

Therefore, the zero of f(x) is x = -10.