Question

Simplify.a2 + 7a - 8a2 + ба - 7Step 1Factor the numerator and the denominator.(a - 1a2 + 7a - 8a2 + 6a - 71)( 1(a - 1)(a + 7)SubmitSkip (you cannot come back)

Answer 1

Given:

`\frac{a^2\text{ + 7a - 8}}{a^2\text{ + 6a - 7}}`

First, we factor out both numerator and denominator using factorization method:

`\begin{gathered} \frac{a^2\text{ + 8a - a - 8}}{a^2\text{ + 7a - a - 7}} \\ =\text{ }\frac{a(a\text{ + 8) -1(a + 8)}}{a(a\text{ + 7) - 1(a + 7)}} \\ =\text{ }\frac{(a\text{ - 1)(a + 8)}}{(a\text{ - 1)(a + 7)}} \end{gathered}`

Next, we can cancel out the common factor:

`=\frac{a\text{ + 8}}{a\text{ + 7}}`

Since, we cannot simplify further, the answer is

`=\frac{a\text{ + 8}}{a\text{ + 7}}`