Question

The town's population increased from 80,000 to 90,000 in ten years. What was the percent of increase?

Answer 1

`12.5\%`

1) We can solve this problem by writing the following ratios and then cross multiplying

2) Note that we're going to consider 80,000 as the 100%

`\begin{gathered} 80,000-------100\% \\ 90,000-------x \\ x=(90000\cdot100)/(80000) \\ x=(90000)/(800)=112.5 \end{gathered}`

We can now subtract 100 from that 112.5

`112.5\%-100\%=12.5\%`

3)Thus the percent of increase in that town was:

`12.5\%`