Question

An Analogical Wage Schedule with Uniformed Pay-hike Similar to the concept of Motion with a Uniformed Acceleration as follows:

An Analogical Wage Schedule with Uniformed Pay-hike Similar to the concept of Motion with a Uniformed Acceleration as follows: You found a job at a company that promises to reward you with a uniformed hourly wage raise of $0.50/hr² for the next hour after each hour with your hard work and good job done by the end of every hour. If your wage starts at $7.25/hr, and you worked for the company 8-hour per day for a straight of 5 days: (1) What would be your average hourly wage you earned during the entire period?
A)$61.00
B)$20.00
C)$17.25
D)$35.25
E)$27.25
F)$33.00

Answer 1

The average hourly wage earned during the entire period is $2.

Step-by-step explanation:

To find the average hourly wage earned during the entire period, we need to first calculate the total wage earned. The wage starts at $7.25/hr and increases by $0.50/hr² after each hour. We can use the formula for the sum of an arithmetic series to calculate the total wage earned in 8 hours:

Total wage = (first hour wage + last hour wage) * (number of hours / 2)

Total wage = (7.25 + (7.25 + 0.50(8-1))) * (8 / 2)

Total wage = (7.25 + 12.75) * 4 = $80

The average hourly wage can then be obtained by dividing the total wage by the number of hours worked:

Average hourly wage = Total wage / Number of hours

Average hourly wage = $80 / (8 hours/day * 5 days)

Average hourly wage = $80 / 40 = $2

The average hourly wage earned during the entire period is $2.