Question

Write the slope intercept form of the equation of the line passing through the points (-50,18) and (40,-9) ( be sure to use exact values)

Answer 1

Given the points:

(x1, y1) ==> (-50, 18)

(x2, y2) ==> (40, -9)

Take the slope-intercept form:

y = mx + b

Where m is the slope and b is the y-intercept

To write the slope intercept form of the equation, find the slope.

Use the slope formula below:

`m=(y2-y1)/(x2-x1)`

Thus, we have:

`\begin{gathered} m=(-9-18)/(40-(-50))=(-9-18)/(40+50)=(-27)/(90)=-(3)/(10) \\ \\ m=-(3)/(10) \end{gathered}`

Substitute m for -3/10 in y = mx + b

`y=-(3)/(10)x+b`

To find the y-intercept, b, use the point (-50, 18).

Substitute -50 for x and 18 for y:

`\begin{gathered} 18=-(3)/(10)\ast(-50)+b \\ \\ 18=-3(-5)+b \\ \\ 18=15+b \\ \\ \text{Subtract 15 from both sides:} \\ 18-15=15-15+b \\ \\ 3=b \\ \\ b=3 \end{gathered}`

The y-intercept of the equation is 3.

Therefore, the slope intercept form of the equation is:

`y=-(3)/(10)x+3`

ANSWER:

`y=-(3)/(10)x+3`