Question

Cherrie buys 7/9 lb of meat. Danny buys 2 4/7 times as much meat as Cherrie.

a) How much meat, in lb, does Danny buy?
b) How much less meat, in lb, does Cherrie buy than Danny?

Answer 1

a) Danny buys 2 lb of meat. b) Cherrie buys 5/9 lb less meat than Danny.

Step-by-step explanation:

a) To find out how much meat Danny buys, we need to multiply the amount of meat Cherrie buys by 2 4/7. First, we need to convert 7/9 lb to a mixed number, which is 7/9 = 0 7/9. So Cherrie buys 0 7/9 lb of meat. Now, 2 4/7 times 0 7/9 can be found by multiplying the whole numbers, multiplying the fractions, and adding the products. 2 times 0 = 0, 2 times 7/9 = 14/9, and 4/7 times 0 = 0 and 4/7 times 7/9 = 28/63. Adding all the products, we get 0 + 14/9 + 0 + 28/63 = 0 + 14/9 + 0 + 4/9 = 0 + 18/9 = 2, so Danny buys 2 lb of meat.

b) To find out how much less meat Cherrie buys than Danny, we subtract the amount of meat Cherrie buys from the amount of meat Danny buys. Danny buys 2 lb of meat and Cherrie buys 0 7/9 lb of meat. To subtract the mixed numbers, we need to convert them to improper fractions. 0 7/9 = 63/9 and 2 = 18/9. Subtracting 63/9 from 18/9, we get 18/9 - 63/9 = -45/9 = -5. So Cherrie buys 5/9 lb less meat than Danny.