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A bag of mixed nuts contains 18 pecans, 18 walnuts, and 18 almonds. What is the probability of NOT randomly selecting a pecan from the bag?

A. 1/3
B. 1/2
C. 2/3
D. 3/4

User Ile
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1 Answer

5 votes

Final answer:

The probability of not selecting a pecan from a bag containing an equal number of pecans, walnuts, and almonds is 2/3, since there are 36 non-pecan nuts out of a total of 54 nuts.

Step-by-step explanation:

The question asks for the probability of not selecting a pecan from a bag that contains equal numbers of pecans, walnuts, and almonds. The total number of nuts in the bag is 18 pecans + 18 walnuts + 18 almonds = 54 nuts. Since there are 18 pecans, there are 54 - 18 = 36 other nuts.

To calculate the probability of not selecting a pecan, we divide the number of non-pecan nuts by the total number of nuts, which gives us 36/54 = 2/3. Therefore, the probability of not selecting a pecan is 2/3, which is answer choice C.

User Plaban
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