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A child releases a balloon from a height of 9.2 feet above the ground. It begins to rise at a steady rate of 3.8 feet per second. Let t be the time the balloon has been rising in seconds since it was let go. (a) How high is the balloon above the ground after 10 seconds?

User Stevo
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Final answer:

The balloon is 47.2 feet above the ground after 10 seconds, calculated by adding the initial height to the product of the ascent rate and time.

Step-by-step explanation:

To find out how high the balloon is after 10 seconds, we can set up an equation using the given rate of ascent and the initial height. The balloon rises at a steady rate of 3.8 feet per second, and it was released from a height of 9.2 feet above the ground.

The height of the balloon after t seconds can be calculated using the formula:

Height = Initial height + (Rate of ascent × Time)

Plugging in the values:

Height after 10 seconds = 9.2 feet + (3.8 feet/second × 10 seconds)

Height after 10 seconds = 9.2 feet + 38 feet

Height after 10 seconds = 47.2 feet

Therefore, the balloon is 47.2 feet above the ground after 10 seconds.

User Snowbldr
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