Final answer:
To have $10,000 in ten years in an account that pays 10% interest compounded annually, you need to deposit $3,874.77.
Step-by-step explanation:
The question is asking how much money needs to be deposited in a bank account that pays 10% interest compounded annually in order to have $10,000 in ten years. To find this, we can use the formula for compound interest: A = P(1+r/n)^(nt), where A is the final amount, P is the principal amount (the initial deposit), r is the annual interest rate, n is the number of times that interest is compounded per year, and t is the number of years.Given that the desired amount is $10,000, the interest rate is 10% (or 0.10), and the number of years is 10, we need to solve the equation: 10,000 = P(1+0.10/1)^(1*10).By solving for P, we find that the principal amount needs to be $3,874.77.