Question

Acceleration Tecle, with a mass of 65.0 kg, is standing on an ice-skating rink. His friend applies a force of 9.0 N to him. What is Tecle's resulting acceleration?

A. 0.138 m/s²
B. 0.139 m/s²
C. 0.140 m/s²
D. 0.137 m/s²

Answer 1

Tecle’s resulting acceleration should be equal to A: 0.138 m/s^2

Answer 2

Tecle's resulting acceleration, when a force of 9.0 N is applied to his 65.0 kg mass, is calculated using Newton's second law of motion. The acceleration is found to be 0.138 m/s².

Step-by-step explanation:

The student is asking about the resulting acceleration of an ice skater named Tecle, who has a mass of 65.0 kg, when a force of 9.0 N is applied to him. To solve this, we use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass (a = F/m).

Using the formula, a = F/m, we substitute Tecle's mass (m) and the net force (F):

a = 9.0 N / 65.0 kg = 0.13846154 m/s²

This can be rounded to three decimal places, giving us an acceleration of 0.138 m/s², which corresponds to answer option A.