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For Saturday night's play, 125 tickets were sold, totaling $1,140. If the price of an adult ticket is $12 and the price of a child's ticket is $6, how many adult tickets and how many child tickets were sold?

A. 60 adult tickets and 65 child tickets.
B. 50 adult tickets and 75 child tickets.
C. 45 adult tickets and 80 child tickets.

1 Answer

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Final answer:

To find the number of adult and child tickets sold, we can set up a system of equations using the given information. By solving this system, we can determine that 65 adult tickets and 60 child tickets were sold.

Step-by-step explanation:

To solve this problem, we need to set up a system of equations using the given information. Let's assume that x represents the number of adult tickets and y represents the number of child tickets.

The total number of tickets sold is 125, so we have the equation x + y = 125.

The total revenue from ticket sales is $1140, so we have the equation 12x + 6y = 1140.

To solve this system, we can use a method like substitution or elimination. Let's use the substitution method:

From the first equation, we can express x in terms of y: x = 125 - y.

Substituting this value of x into the second equation, we get 12(125 - y) + 6y = 1140.

Simplifying this equation, we have 1500 - 12y + 6y = 1140.

Combining like terms, we get -6y = -360.

Dividing both sides by -6, we find that y = 60.

Substituting this value of y back into the first equation, we find that x = 125 - 60 = 65.

Therefore, 65 adult tickets and 60 child tickets were sold, which corresponds to option A.

User JonnyG
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