Final answer:
The area corresponding to Z > -3.41 is approximately 99.865% of the total area under the standard normal curve, obtained by subtracting the very small area to the left of z = -3.41 from 1.
Step-by-step explanation:
The question pertains to the concept of normal distribution and the calculation of probabilities using z-scores. The specific query is finding the area under the normal curve for a z-score greater than -3.41. Using the z-table, one would look up the area to the left of z = -3.41, which, due to the symmetry of the normal distribution, is very small. Since the total area under the normal curve is 1, the region of interest, which is the area to the right of z = -3.41, would be 1 minus the area to the left of z = -3.41. Although the exact value is not given in the provided reference information, we know from the empirical rule that about 99.7% of values lie within three standard deviations of the mean, hence the area to the left of z = -3 is approximately 0.00135 (0.1% of 99.7%). Therefore, the area to the right of z = -3.41 is approximately 1 - 0.00135, which equals approximately 0.99865 or 99.865%.