121k views
1 vote
What are the none permissible values for (2x)/(6x-4x²)

User Donal M
by
8.8k points

1 Answer

3 votes

Final answer:

The none permissible values for the expression (2x)/(6x-4x^2) can be found by setting the denominator equal to zero and solving for x.

Step-by-step explanation:

The none permissible values for the expression (2x)/(6x-4x^2) can be found by setting the denominator equal to zero and solving for x. In this case, the denominator is 6x-4x^2. To find the values of x, we set 6x-4x^2 = 0 and solve for x using the quadratic equation. Once we have the solutions, we can determine which values of x make the denominator equal to zero and are therefore not permissible.

User Gianni Carlo
by
8.1k points

No related questions found