Question

I need help with #5 using info from number 4.

Answer 1

The figure below illustrate the situation

Using sine rule it follows:

`\begin{gathered} (\sin92)/(16.37)=(\sin66.3)/(a) \\ a=15.0 \end{gathered}`

Also

`\begin{gathered} (\sin92)/(16.37)=(\sin21.7)/(b) \\ b=6.06 \end{gathered}`

The vectors are defined by

`\begin{gathered} P=(a\cos15)i+(-a\sin15)j \\ C=(-b\sin17)i+(-bcos17)j \end{gathered}`

Substituting the the value of a and b into the vectors

It follows:

`\begin{gathered} P=(15\cos15)i+(-15\sin15)j \\ P=14.49i-3.88j \end{gathered}`

Also

`\begin{gathered} C=(-6.06\sin17)i+(-6.06\cos17)j \\ C=-1.77i-5.80j \end{gathered}`

Therefore the vectors are:

`\begin{gathered} P=14.49\imaginaryI-3.88j \\ C=-1.77\imaginaryI-5.80j \end{gathered}`