Question

3. Hershey's is going to make a special edition chocolate bar with dimensions 2 times the size of theregular chocolate bar. If the regular bar has a volume of 38.5 cm, what is the volume of the specialedition bar?

Answer 1

A bar has the form of a rectangular prism, the volume of this kind of figure is given by the following formula:

`V=l* w* h`

Where l is the length, w is the width and h is the height of the bar.

Let's call l1, w1 and h1 to the length, width and height of the regular chocolate bar, by replacing them into the above formula we get 38.5 cubic centimeters for the volume:

`38.5=l1* w1* h1`

Now, Let's call l2, w2, and h2 to the length, width, and height of the special edition chocolate bar. We are told that the dimensions of this bar are two times the dimensions of the regular one, then:

l2 = 2×l1

w2 = 2×w1

h2 = 2×h1

By dividing by two on both sides of these expressions, we get:

`\begin{gathered} l1=(l2)/(2) \\ w1=(w2)/(2) \\ h1=(h2)/(2) \end{gathered}`

By replacing these into the equation of the volume for the regular bar, we get:

`\begin{gathered} 38.5=(l2)/(2)*(w2)/(2)*(h2)/(2) \\ 38.5=\frac{l2* w2* h2}{2*2*2^{}} \\ 38.5=\frac{l2* w2* h2}{8^{}} \\ 38.5*8=l2* w2* h2 \\ 308=l2* w2* h2 \\ l2* w2* h2=308 \\ V2=308 \end{gathered}`

Then, the volume of the special edition bar (V2) equals 308 cubic centimeters