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Three years ago, you invested 3050$. Today, it is worth 3800$. What rate of interest did you earn?

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Final answer:

The interest rate earned on an investment that increased from $3050 to $3800 over three years is approximately 8.20%.

Step-by-step explanation:

The question is asking to determine the rate of interest earned on an investment that increased from $3050 to $3800 over three years. To calculate the interest rate, we need to use the formula for simple interest, which can be rearranged from I = Prt, where:

  • I is the interest earned or the increase in value,
  • P is the principal amount (the initial investment),
  • r is the rate of interest per period,
  • t is the time the money is invested for.

In this case, I = $3800 - $3050 = $750, P = $3050, and t = 3 years. Plugging into the formula and solving for r gives us the annual interest rate.

The calculation is as follows:

750 = 3050 × r × 3

750 = 9150r

r = 750 / 9150

r = 0.08196721311 or 8.20% when rounded to two decimal places.

Therefore, the annual rate of interest earned on the investment was approximately 8.20%.

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