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You are transmitting a 10000 bits packet over a 2000 km fiber option link. how fast slow should the transmission rate on the link be so that the propagation delay on the link should be approximately equal to the packet transmission time?

User JoyGuru
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Final answer:

The transmission rate on the link should be 1 Mbps (megabits per second) so that the propagation delay on the link is approximately equal to the packet transmission time.

Step-by-step explanation:

To determine the transmission rate on the link, we need to calculate the propagation delay of the signal and compare it to the packet transmission time. The propagation delay is the time it takes for the signal to travel the distance of the fiber optic link. The packet transmission time is the time it takes to transmit a 10,000 bit packet.

First, we need to calculate the propagation delay. We know the distance of the link is 2000 km, so we can use the formula: propagation delay = distance / speed of light. The speed of light in fiber optic cables is about 200,000 km/s. Plugging in the values, we get:

propagation delay = 2000 km / 200,000 km/s = 0.01 s = 10 ms.

Next, we need to calculate the packet transmission time. The transmission rate is the number of bits transmitted in one second. We can use the formula: transmission time = packet size / transmission rate. Plugging in the values, we get:

packet transmission time = 10,000 bits / transmission rate.

Since we want the propagation delay to be approximately equal to the packet transmission time, we set them equal to each other and solve for the transmission rate:

transmission rate = 10 ms^{-1} / 10,000 bits = 10^{-6} ms^{-1}.

So, the transmission rate on the link should be 10^{-6} ms^{-1} or 1 Mbps (megabits per second).

User MateuszL
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