Question

run the program. Note that there is no syntax error in the program (i.e., the program can be built successfully). Hint: the error is related to the parameter passing (refer to Lecture\#16 Slides 5-10 if necessary). The program is supposed to code a number by extracting the least significant digit (LSD) of the number using the modulo % operation and then adding this digit to the number. Example (Test Case): if you input the original number 1254, the coded number will be 1258 , which is obtained by adding the LSD 4 to 1254 . The expected correct output from the program should be: The value of a before the function call is: 1254 The value of a after the coding is: 1258 You may use the debugging functions in Visual Studio you have learned from Lab\#7 to help you identify the error if necessary. printf("The value of a before the function call is: \%d \\",a); code(a); printf("The value of a after the coding is: \%d \\",a); void code(int m) int lsd;

Answer 1

The issue lies in the parameter passing method of the 'code' function. To correct it, the function should either return the coded value or change the parameter to be passed by reference to modify the original variable directly.

Step-by-step explanation:

The issue described here is a common error in programming related to parameter passing. When the function code(int m) is called, it's supposed to alter the value of the variable a by adding its least significant digit (LSD) to it. However, because the function receives the parameter by value, it only modifies the local copy of the variable within the function, leaving the original variable a unchanged outside the function. To solve this, the function should be modified to either return the new value or accept the variable by reference using a pointer or a reference parameter, depending on the programming language used.

To make the code function work as intended, it should return the modified value or modify the argument by reference. So the function prototype should be either int code(int m), if it returns the new value, or void code(int* m), if the parameter is passed by reference. In case of the latter, the body of the function would also involve dereferencing the pointer to modify the value it points to.