Question

Given an integer list with two elements, return True if the list contains a 2 or a 3.

has23 ([2,5])→ returns True
has23 ([4,3])→ returns True
has23 ([4,5])→ returns False
def has23 (nums): If len(nums) =2 Result = True Elif len(nums)=3 Result = True Else: Result = false

Answer 1

The question pertains to creating a Python function that checks if a list contains a 2 or a 3. The correct function implementation uses a simple return statement to check the list regardless of its size, utilizing the 'in' keyword for membership testing.

Step-by-step explanation:

The subject of this question is Computers and Technology, specifically dealing with basic programming logic and function implementation. To determine if an integer list contains a 2 or a 3, the given Python function has23 needs to verify each element within the list. The correct implementation below checks for the presence of 2 or 3 in any size of list, not just ones with two elements:

def has23(nums):
return 2 in nums or 3 in nums

This function simply checks if either 2 or 3 is an element of the list nums and returns True if so, or False otherwise. It is written in Python and demonstrates conditional expressions and the in keyword for checking membership within an iterable.