Final answer:
To derive the algorithm, we can express the number 2 as eln 2 and apply properties of logarithms. The algorithm can be derived as z' = 2' and x' = log_2 y, with the condition 2^x' ≤ y < 2^(x'+1).
Step-by-step explanation:
Using the method of invariants to derive an algorithm:
Step 1:
We can start by expressing the number 2 as
eln 2
since the exponential and natural logarithm are inverse functions. For the special case of doubling (b=2), we have
2 = eln 2
.
Step 2:
Next, we can apply the property of logarithms that the logarithm of a product of two numbers is the sum of the logarithms of the two numbers, which means that
log xy = log x + log y
. In this case, we have
log z' = log 2' + log(y < 2^(x'+1))
.
Step 3:
To derive the algorithm, we'll continue applying properties of logarithms and simplifying the equation.
Final Algorithm:
The algorithm can be derived as follows:
z' = 2'
x' = log_2 y
2^x' ≤ y < 2^(x'+1)