Final answer:
All the given statements A, C, and D are valid considering the expected behavior of the defined squareRoot function, which returns a double value that can be stored in the variable y.
Step-by-step explanation:
Given the definitions of the functions double squareRoot(double x) and void printVal(double x), and the variable double y; we can determine the validity of the given statements. Considering these definitions, let's evaluate the statements:
- A. y = squareRoot(49.0): This is a valid statement, as squareRoot is a function that would logically return the square root of its argument, which can be assigned to the variable y.
- C. y = 1.0 + squareRoot(144.0): This is also valid, adding 1.0 to the square root of 144, which is calculated by the squareRoot function, and assigning the result to y.
- D. y = squareRoot(squareRoot(16.0)): This is valid. It first takes the square root of 16, which is 4, and then takes the square root of 4, which results in 2, and assigns this value to y.
The usage of the squareRoot function in these contexts is similar to raising a number to the power of 0.5 (also expressed as taking the square root). The statements A, C, and D are all valid based on the function's expected behavior to return a double value that can be assigned to a variable.