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Find the probability P(−1.90≤Z≤0)
a.0.4710
b.0.0290
c.0.0580
d.0.5290

User Eff
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1 Answer

4 votes

Final answer:

The probability P(-1.90≤Z≤0) is found by subtracting the area to the left of Z = -1.90 from the area to the left of Z = 0. The closest answer to the calculated value of 0.4713 is option (a) 0.4710.

Step-by-step explanation:

To find the probability P(-1.90≤Z≤0), we look up the area/percentile to the left of Z = -1.90 in the z-table and subtract it from the area to the left of Z = 0 (since the area to the left of Z = 0 is 0.5). If we look at the standard normal distribution table, the area to the left of Z = -1.90 is about 0.0287. Therefore, the probability that Z is between -1.90 and 0 is:

0.5 (area to the left of Z = 0) - 0.0287 (area to the left of Z = -1.90) = 0.4713.

However, as this result is not present in the given options, we must look at the options provided and select the one that is closest to our calculated value. The closest option to our calculated value is option (a) 0.4710.

User Vecnas
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