Question

Please answer this question and show a graph table and work please.

Answer 1

The equation is

`y=(3^x)/(4)`

Set x=-2, we get

`y=(3^(-2))/(4)`
`\text{ Use }a^(-n)=(1)/(a^n)\text{.}`

`y=(1)/(3^2*4)=(1)/(9*4)`

`y=(1)/(36)=0.028`
`\text{The point is (-2,0.028})`

set x=-1, we get

`y=(3^(-1))/(4)`

`y=(1)/(3*4)=(1)/(12)=0.08`
`\text{The point is (-1,0.08})`

Set x=0, we get

`y=(3^0)/(4)=(1)/(4)=0.25`

`\text{The point is (0,0.25})`

Set x=1,we get

`y=(3^1)/(4)=(3)/(4)`

`\text{The point is (1,}(3)/(4))`

Set x=2, we get

`y=(3^2)/(4)=(9)/(4)`

`\text{The point is (2,}(9)/(4))`

The table is

`\begin{gathered} x\text{ = -2 -1 0 1 2 4} \\ y\text{ = }(1)/(36)\text{ }(1)/(12)\text{ }(1)/(4)\text{ }(3)/(4)\text{ }(9)/(4)\text{ }(81)/(4) \end{gathered}`

`\begin{gathered} x\text{ = -2 \_\_\_\_\_\_-1 \_\_\_\_\_\_0\_\_\_ \_\_\_1\_\_\_\_\_\_\_ 2 } \\ y\text{ = 0.028\_\_\_\_0.083\_\_\_\_}0.25_(---)_{}0.75--2.25 \end{gathered}`

Mark all the points on the graph and connect them all as follows.