Final answer:
The recurrence relation for the nth square is a_n = a_n-1 + 2n - 1. By plugging in the values of n starting from 1, we can find the nth square.
Step-by-step explanation:
The recurrence relation for the nth square can be defined as:
an = an-1 + 2n - 1
To solve this recurrence relation, we can use the initial condition that a1 = 1 (since the first square is 1).
Using this recurrence relation, we can find the nth square by plugging in the values of n starting from 1:
a1 = 1
a2 = a1 + 2(2) - 1 = 4
a3 = a2 + 2(3) - 1 = 9
a4 = a3 + 2(4) - 1 = 16
and so on...