Question

Import re str2 = "the midterm had regular expression questions on it" match = re.search (r′ (?<=)r.∗ r(?=)′ ,str2) print(match.group ())

a)regular # note that there are spaces before and after
b)regular
c)rm had regular expr
d)there is no match - trick question!

Answer 1

The given code snippet uses regular expressions to search for a pattern within a string, but the pattern does not exist in the given string.

Step-by-step explanation:

The given code snippet is written in Python and uses regular expressions to search for a pattern within a string. In this case, the code is searching for a substring that starts with 'r' and ends with 'r', where any character can be present between the two 'r's. The re.search() function is used to find the first occurrence of this pattern in the given string.

The correct answer is d) there is no match - trick question! because the regular expression pattern does not exist in the given string. The pattern '(?<=)r.*r(?=)' looks for characters between 'r' and 'r', but there are no 'r's present in the given string to create a match.

It is important to note that the pattern used in the regular expression is case sensitive, meaning it will only match lowercase 'r' characters in the given string.

Therefore the correct answer is b) regular.