Question

Why with a vector called v, is v[v.size()] a range error? What would be the result of calling this, assuming it was allowed to execute this statement?

Answer 1

Accessing an element at v[v.size()] in a vector will result in a range error.

Step-by-step explanation:

When working with a vector called v, accessing v[v.size()] would result in a range error. The reason for this is that the indices of a vector in most programming languages start from 0. So, the last element in a vector is actually at the index v.size() - 1 and not v.size().

For example, let's say we have a vector of integers with 5 elements: [2, 4, 6, 8, 10]. The elements of this vector are stored at indices 0 to 4. If we try to access v[5], we would be trying to access an element outside the valid range of indices, which would result in a range error.

Therefore, calling v[v.size()] would be an invalid statement and would cause a range error in most programming languages.